Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 64
If x + y + z = 19, $$x^2 +y^2 + z^2 = 133$$ and $$xz = y^2$$, then the difference between z and x is:
Solution
x + y + z = 19
$$(x + y + z)^2 = x^2 + y^2 +z^2 + 2(xy + yz +zx) $$
361 = 133 + 2(xy + yz +zx)
xy + yz +zx= 114
Substituting xz = y$$^2$$
xy+yz+y$$^2$$ = 114
y(x + y + z) =114
y=6
x+z=13
xz=$$y^2$$ = 36
x - z = $$\sqrt{ (x + z)^2 - 4xz}$$
= $$\sqrt{ 169 - 144}$$
=5
So , the answer would be Option a)5.
Video Solution
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
