If the 8-digit number 43A5325B is divisible by 8 and 9, then the sum of A and B is equal to:

Given, 8-digit number 43A5325B is divisible by 8 and 9

If the number is divisible by 8, then the last three digits should be divisible by 8

$$\Rightarrow$$ 25B is divisible by 8

$$\Rightarrow$$  B = 6

If the number is divisible by 9, then the sum of the digits of the number should be divisible by 9

$$\Rightarrow$$ 4 + 3 + A + 5 + 3 + 2 + 5 + B = multiple of 9

$$\Rightarrow$$ 22 + A + B = multiple of 9

$$\Rightarrow$$ 22 + A + 6 = multiple of 9

$$\Rightarrow$$ 28 + A = multiple of 9

The only possible value of A is 8

$$\therefore\ $$Sum of A and B = 8 + 6 = 14

Hence, the correct answer is Option B