Question 64

If $$\frac{x}{a+b}+1=\frac{x}{a-b}+\frac{a-b}{a+b}$$, then value of $$x$$ is

Solution

Expression : $$\frac{x}{a+b}+1=\frac{x}{a-b}+\frac{a-b}{a+b}$$

=> $$\frac{x}{a+b}-\frac{x}{a-b}=\frac{a-b}{a+b}-1$$

=> $$\frac{x(a-b)-x(a+b)}{(a+b)(a-b)}=\frac{(a-b)-(a+b)}{a+b}$$

=> $$\frac{-2bx}{a-b} = -2b$$

=> $$x = (a-b)$$

=> Ans - (C)

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: