Given, 10-digit number 67127y76x2 is divisible by 88 then the number must be divisible by 8 and 11.
If the number is divisible by 8, then the last three digits should be divisible by 8
$$\Rightarrow$$Â 6x2 is divisible by 8
$$\Rightarrow$$Â x = 3
If the number is divisible by 11 then,
Sum of digits at even place - Sum of digits at odd place = 0 or multiple of 11
$$\Rightarrow$$Â (7+2+y+6+2)-(6+1+7+7+x) =Â 0 or multiple of 11
$$\Rightarrow$$Â 17 + y - 21 - x =Â 0 or multiple of 11
$$\Rightarrow$$Â 17 + y - 21 - 3 =Â 0 or multiple of 11
$$\Rightarrow$$Â y - 7 = 0 or multiple of 11
The only possibility is y - 7 = 0
$$\Rightarrow$$Â y = 7
$$\therefore\ $$7x - 2y = 7(3) - 2(7) = 21 - 14 = 7
Hence, the correct answer is Option B
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