How many men will be required to plough 50 acres of land in 10 days if 15 men required 6 days to plough 10 acres of land?

15 men can plough 10 acres of land in 6 days

$$=$$> $$M_1$$ = 15,   $$D_1$$ = 6,   $$W_1$$ = 10

Let the number of men required to plough 50 acres of land in 10 days = $$M_2$$

Given, $$D_2$$ = 10,  $$W_2$$ = 50

We know that $$\frac{M_1D_1}{W_1}=\frac{M_2D_2}{W_2}$$

$$=$$>  $$\frac{15\times6}{10}=\frac{M_2\times10}{50}$$

$$=$$>  $$M_2=45$$

$$\therefore\ $$The number of men required to plough 50 acres of land in 10 days = 45

Hence, the correct answer is Option D