Suppose $$\theta \in [0, \frac{\pi}{4}]$$ is a solution of $$4\cos\theta - 3\sin\theta = 1$$. Then $$\cos\theta$$ is equal to :

A

$$\frac{4}{(3\sqrt{6}+2)}$$

B

$$\frac{6+\sqrt{6}}{(3\sqrt{6}+2)}$$

C

$$\frac{4}{(3\sqrt{6}-2)}$$

D

$$\frac{6-\sqrt{6}}{(3\sqrt{6}-2)}$$