Let $$C$$ be the circle in the complex plane with centre $$z_0 = \frac{1}{2}(1 + 3i)$$ and radius $$r = 1$$. Let $$z_1 = 1 + i$$ and the complex number $$z_2$$ be outside circle $$C$$ such that $$|z_1 - z_0||z_2 - z_0| = 1$$. If $$z_0$$, $$z_1$$ and $$z_2$$ are collinear, then the smaller value of $$|z_2|^2$$ is equal to

A

$$\frac{5}{2}$$

B

$$\frac{7}{2}$$

C

$$\frac{13}{2}$$

D

$$\frac{3}{2}$$