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Consider an elementary reaction $$A(g)+B(g)\rightarrow C(g)+D(g)$$ If the volume of reaction mixture is suddenly reduced to $$\frac{1}{3}$$ of its initial volume, the reaction rate will become 'x' times of the original reaction rate. The value of x is :
Volume reduced to 1/3: concentrations triple. Rate = k[A][B] → new rate = k(3[A])(3[B]) = 9k[A][B] = 9× original rate. x = 9.
The correct answer is Option 3: 9.
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