Question 61

If cot(A + B) = x, then value of x is

Expression : cot(A + B) = x

= $$\frac{cos(A + B)}{sin(A + B)}$$

= $$\frac{cosAcosB - sinAsinB}{sinAcosB + cosAsinB}$$

Dividing both numerator and denominator by $$(sinAsinB)$$, we get :

= $$\frac{cosAcosB - sinAsinB}{sinAsinB} \div \frac{sinAcosB + cosAsinB}{sinAsinB}$$

= $$(\frac{cosAcosB}{sinAsinB} - 1) \div (\frac{cosB}{sinB} + \frac{cosA}{sinA})$$

= $$\frac{cotAcotB - 1}{cotB + cotA}$$

=> Ans - (C)

Get AI Help

Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

Join CAT 2026 course by 5-Time CAT 100%iler

Crack CAT 2026 & Other Exams with Cracku!

Ask AI

Ask our AI anything

AI can make mistakes. Please verify important information.