What is the perpendicular distance (in cm) between the parallel sides of a trapezium whose area is 108 sq cm. and the lengths of the parallel sides are 9 cm and 36 cm?
Area of a trapezium = $$\dfrac{1}{2}\times\text{Sum of lengths of opposite sides}\times\text{Perpendicular distance between them}$$
=> $$108 = \dfrac{1}{2}\times(36+9)\times D$$
=> $$D = \dfrac{216}{45} = 4.8 cm$$
Therefore, Perpendicular distance between the sides = 4.8 cm.
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