The perimeter of an equilateral triangle is equal to the circumference of a circle. If each side of this equilateral triangle is 88 cm long, then what will be the length of the diameter of the circle mentioned above? [Use $$\pi = \frac{22}{7}$$]

The perimeter of an equilateral triangle is equal to the circumference of a circle.

perimeter of an equilateral triangle = circumference of a circle

$$3\times\ length\ of\ each\ side\ of\ equilateral\ triangle\ =\ 2\times\ \pi\ \times\ radius$$

If each side of this equilateral triangle is 88 cm long.

$$3\times88\ =\ 2\times\frac{22}{7}\ \times\ radius$$

$$3\times2\ =\ \frac{1}{7}\ \times\ radius$$
$$6\ =\ \frac{1}{7}\ \times\ radius$$
radius of the circle = 42 cm

length of the diameter of the circle mentioned above = $$2\times radius$$

= $$2\times 42$$

= 84 cm