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The average marks of 42 students in an examination, was 64. Later it was found that the marks of three students were misread as 72, 58 and 44 instead of the actual marks 64, 42 and 26 respectively. What is the correct average marks?
The average marks of 42 students in an examination $$= 64$$
Total Marks $$=42\times64 = 2688$$
Later it was found that the marks of three students were misread as 72, 58 and 44 instead of the actual marks 64, 42 and 26 respectively.
Therefore, the actual average is $$=\frac{2688-(72+58+44)+(64+42+26)}{42}=63$$
Option C is correct.
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