Solution
In the given figure, $$\triangle$$ ABC is right angled triangle.
=> $$\angle$$ D = $$90^\circ-60^\circ=30^\circ$$
Thus, in $$\triangle$$ ACD, we have $$\angle$$ CAD = $$\angle$$ ADC = $$30^\circ$$
$$\therefore$$ AC = CD [Sides opposite to equal angles are equal.]
=> Ans - (B)
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