Question 6

Calculate the length of the tangent (in cm) which is drawn from a point at a distance of 13 cm from the centre and the largest chord of that circle is 10 cm.

Solution

Given : Largest chord in a circle is the diameter, => radius OA = $$\frac{10}{2}=5$$ cm and OB = $$13$$ cm

To find : AB = ?

Solution : In right $$\triangle$$ OAB,

=> $$(AB)^2=(OB)^2-(OA)^2$$

=> $$(AB)^2=(13)^2-(5)^2$$

=> $$(AB)^2=169-25=144$$

=> $$AB=\sqrt{144}=12$$ cm

=> Ans - (B)

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