Calculate the angle subtended by the chord at the point on the major arc if the radius and the chord of the circle are equal in length.

Given : Radius and the chord of the circle are equal in length.

To find : $$\angle$$ ACB = ?

Solution : It is given that the radius and the chord of the circle are equal in length.

=> OA = OB = AB

=> AOB is an equilateral triangle, => $$\angle$$ AOB = $$60^\circ$$

Now, the angle subtended by an arc at the centre is double the angle subtended by it at any point on the circle.

=> $$\angle$$ ACB = $$\frac{60}{2}=30^\circ$$

=> Ans - (A)