Question 59

Two students appeared for an examination. One of them secured 24 marks more than the other and his marks were 65% of the sum of their marks. The marks obtained by them are .

Solution

Let marks scored by 1st student = $$x$$

=> Marks scored by another student = $$(x + 24)$$

According to question, => $$(x + 24) = \frac{65}{100} \times (x + x + 24)$$

=> $$x + 24 = \frac{13}{10} \times (x + 12)$$

=> $$10x + 240 = 13x + 156$$

=> $$13x - 10x = 240 - 156 = 84$$

=> $$x = \frac{84}{3} = 28$$

$$\therefore$$ Marks scored by other student = 28 + 24 = 52

=> Ans - (D)

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