Question 59

The following bar chart shows the quantity (in million kg) of grains exported by a country from 2013-2018.

By how much percent is the maximum export greater than the minimum export during the given period?

Solution

maximum export was in 2018. It is 37500.

minimum export was in 2015. It is 18750.

Percentage more = $$\frac{37500-18750}{18750}\times\ 100$$

= $$\frac{18750}{18750}\times\ 100$$

= 100%


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