Question 59

The circumference of the base of a conical tent is 66 m.If the height of the tent is 36 m, what is the area (in m$$^2$$) of the canvas used in making the tent?(Take $$\pi = \frac{22}{7}$$)

Solution

The circumference of the base of a conical tent = 66 m

$$2\pi r $$ = 66

r = $$\frac{33}{\frac{22}{7}}$$ = 21/2 m

h = 36 m

l = $$\sqrt{r^2 + h^2}$$

= $$\sqrt{(\frac{21}{2})^2 + 36^2}$$ = $$\sqrt{\frac{441}{4} + 1296}$$

= $$75/2$$ = 37.5

Area of canvas = $$\pi r l = \frac{22}{7} \times \frac{21}{2} \times 37.5$$ = 1237.5 sqm

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