Question 59

The average of 27 numbers is zero. Out of them, how many maybe greater than zero, at the most?

Solution

As per the question,

There are 27 numbers, the average of 27 numbers =0

So, here minimum 26 number can be greater than 0, $$x_1+x_2......+x_{26}-X_{27}=0$$

the sum of 26 numbers can be equal the -27th number which is negative and less than 0, and the sum can be zero.

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