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Question 58

The difference in the 'spin-only' magnetic moment values of $$KMnO_4$$ and the manganese product formed during titration of $$KMnO_4$$ against oxalic acid in acidic medium is _______ BM. (nearest integer)


Correct Answer: 6

Solution

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KMnO₄: Mn⁷⁺ (d⁰), μ = 0 BM.

In acidic medium titration with oxalic acid: KMnO₄ → Mn²⁺. Mn²⁺ (d⁵), μ = √(5×7) = √35 = 5.92 ≈ 6 BM.

Difference = |0 - 6| = 6 BM.

The answer is 6.

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