The difference in the 'spin-only' magnetic moment values of $$KMnO_4$$ and the manganese product formed during titration of $$KMnO_4$$ against oxalic acid in acidic medium is _______ BM. (nearest integer)

Correct Answer: 6

KMnO₄: Mn⁷⁺ (d⁰), μ = 0 BM.

In acidic medium titration with oxalic acid: KMnO₄ → Mn²⁺. Mn²⁺ (d⁵), μ = √(5×7) = √35 = 5.92 ≈ 6 BM.

Difference = |0 - 6| = 6 BM.

The answer is 6.

Create a FREE account and get:

Predict your JEE Main percentile, rank & performance in seconds

Check Your Score Now

Ask our AI anything

AI can make mistakes. Please verify important information.

The difference in the &#x27;spin-only&#x27; magnetic moment values of $$KMnO_4$$ and the manganese product formed during titration of $$KMnO_4$$ against oxalic acid in acidic medium is _______ BM. (nearest integer)