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Among $$CrO$$, $$Cr_2O_3$$ and $$CrO_3$$, the sum of spin-only magnetic moment values of basic and amphoteric oxides is _______ $$\times 10^{-2}$$ BM (nearest integer). (Given atomic number of Cr is 24)
Correct Answer: 877
CrO: Cr²⁺ (d⁴), basic oxide. μ = √(4×6) = √24 = 4.90 BM.
Cr₂O₃: Cr³⁺ (d³), amphoteric oxide. μ = √(3×5) = √15 = 3.87 BM.
CrO₃: Cr⁶⁺ (d⁰), acidic oxide. μ = 0 BM.
Sum of basic and amphoteric = 4.90 + 3.87 = 8.77 BM = 877 × 10⁻² BM.
The answer is 877.
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