If $$(x - 2) (x - p) = x^{2}- ax+ 6$$, then the value of (a -p) is
$$(x - 2) (x - p) =Â x^{2}- ax+ 6$$
$$\Rightarrow$$ $$x^{2} - (2 + p)x+ 2p =Â x^{2}- ax+ 6$$
By the compare of terms,
a = 2 + p, 2p = 6
p = 3 and a = 2 + 3 = 5
The value of (a - p) = 5 - 3 = 2
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