An equilateral triangle and regular hexagon have the same perimeter. The ratio of the area of the triangle to that of the hexagon is
Let side of equilateral triangle = $$a$$ and side of regular hexagon = $$s$$
According to ques, => $$3a=6s$$
=> $$a=2s$$
Now, ratio of the area of the triangle to that of the hexagon :
= $$(\frac{\sqrt3}{4} a^2):(\frac{3\sqrt3}{2}s^2)$$
=> $$\frac{1}{2} (2s)^2=3s^2$$
=> $$2:3$$
=> Ans - (B)
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