An article is sold for ₹ 810 at a loss of 10%. What should be the selling price if the loss is 20%?

selling price = 810

cost price = 100

Loss of 1st article = $$\frac{10}{100}\times100$$

                                 = 10
selling price = c.p - loss

                   = 100 - 10

                   = 90

90=810(given)

1= 9

c.p = $$100\times 9$$

      = 900  

  In 2nd article

Cost price is same= 900

Loss of 2nd article = $$\frac{20}{100}\times900$$

                                 = 180

s.p = c.p - loss

      = $$900- 180$$

      = Rs 720