Two students, A and B, appeared for an examination. A secured 8 marks more than B and the marks of the former was 55% of the sum of their marks. The sum of the marks obtained by A and B is:
Let the marks secured by B be xÂ
Therefore marks secured by A will be x+8
Now , sum of marks obtained by A and B will be x+x+8 = 2x+8
Now marks of A = 55% of marks of (A + B)
$$x+8=\frac{55}{100}\times\ \left(x+x+8\right)$$
0.55(2x+8) =x+8
we get 1.1x+4.4 =x+8
0.1x=3.6
x=36
Therefore sum of marks obtained by A and B will be 2x+8
= 2(36) +8
= 72+8
= 80
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