The radius of the base of a cylinder is 7 cm and its curved surface area is 440 cm$$^2$$. Its volume (in cm$$^3$$) will be: (Take $$\pi = \frac{22}{7}$$)

Let the height of the cylinder = h
It is given that radius of base of the cylinder $$=7cm$$

surface area of the curved surface of the cylinder $$=440 cm^2$$
$$\pi = \frac{22}{7}$$

We know that, surface area of the curved part of the cylinder $$=2\pi \times r\times h$$
Now, substituting the values,

$$2\pi \times r\times h=440$$
$$2 \times \dfrac{22}{7} \times 7\times h=440$$
$$ h=\dfrac{440}{2\times 22}$$
$$ h=10cm$$
Hence, the volume of the cylinder $$V=\pi r^2 h$$
$$V= \dfrac{22}{7}\times{7^2} \times10$$
$$V=22\times7\times 10=1540cm^3$$