If the three sides of a triangle are 11 cm, 12 cm and 13 cm, then whatis the area of the given triangle (in cm$$^2$$)?

Given, length of sides of triangle

a=11, b=12, c=13

Semiperimeter of triangle(s) = $$\frac{a+b+c}{2}$$ = $$\frac{11+12+13}{2}$$ = 18

Area of triangle = $$\sqrt{s\left(s-a\right)\left(s-b\right)\left(s-c\right)}$$

$$=\sqrt{18\left(18-11\right)\left(18-12\right)\left(18-13\right)}$$

$$=\sqrt{18\times7\times6\times5}$$

$$=\sqrt{3\times6\times7\times6\times5}$$

$$=6\sqrt{3\times7\times5}$$

$$=6\sqrt{105}$$

Hence, the correct answer is Option C