If a number is divided by 14, then it becomes equal to 10% of the second number. First number is how much percent more than the second number?
Let first number be $$14x$$ and second number be $$y$$
According to ques, => $$x=10\%$$ of $$y$$
=> $$10x=y$$
=> $$\frac{x}{y}=\frac{1}{10}$$
Let $$x=1$$ and $$y=10$$
Numbers are 14 and 10
=> First number is greater than second by = $$\frac{14-10}{10}\times100=40\%$$
=> Ans - (A)
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