Question 57

A first row transition metal with highest enthalpy of atomisation, upon reaction with oxygen at high temperature forms oxides of formula $$M_2O_n$$ (where $$n = 3, 4, 5$$). The 'spin-only' magnetic moment value of the amphoteric oxide from the above oxides is ______ BM (nearest integer). (Given atomic number: Sc: 21, Ti: 22, V: 23, Cr: 24, Mn: 25, Fe: 26, Co: 27, Ni: 28, Cu: 29, Zn: 30)

Correct Answer: 0

Identification of Metal ($$\text{M}$$): Among the 3d transition series, Vanadium ($$\text{V}$$, $$Z=23$$) has the highest enthalpy of atomization.
Oxides Formed: Vanadium forms $$\text{V}_2\text{O}_3$$, $$\text{V}_2\text{O}_4$$, and $$\text{V}_2\text{O}_5$$.
Amphoteric Oxide Selection: $$\text{V}_2\text{O}_5$$ is the characteristic amphoteric oxide in this series.
Magnetic Moment Calculation: In $$\text{V}_2\text{O}_5$$, Vanadium is in its maximum oxidation state of $$+5$$.
$$\text{V}^{5+} = [\text{Ar}] 3d^0 4s^0$$ (Number of unpaired electrons, $$n = 0$$)
$$\text{Spin-only magnetic moment } (\mu) = \sqrt{n(n+2)} = 0\text{ BM}$$

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