Question 57
A can do a work in 15 days. B is 25% more efficient than A. In how many days, working together A and B will complete the same work?
Solution
Let's assume the efficiency of A is '4y'.
B is 25% more efficient than A.
the efficiency of B = 125% of the efficiency of A
= $$\frac{5}{4}\times\ 4y$$
= 5y
A can do a work in 15 days.
Total work = $$15\times4y$$ = 60y
Time taken by A and B together to complete the same work = $$\frac{60y}{4y+5y}$$
= $$\frac{60y}{9y}$$
= $$\frac{20}{3}$$ days
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