Question 57

A can do a work in 15 days. B is 25% more efficient than A. In how many days, working together A and B will complete the same work?

Solution

Let's assume the efficiency of A is '4y'.

B is 25% more efficient than A.

the efficiency of B = 125% of the efficiency of A

= $$\frac{5}{4}\times\ 4y$$

= 5y

A can do a work in 15 days.

Total work = $$15\times4y$$ = 60y

Time taken by A and B together to complete the same work = $$\frac{60y}{4y+5y}$$

= $$\frac{60y}{9y}$$

= $$\frac{20}{3}$$ days

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