The height of a cone is 16 cm and radius of its base is 30 cm.If the rate of painting it is ₹14/cm$$^2$$, then what will be the total cost in painting the curved surface of cone from outside?

Given, Height of the cone = 16 cm
Radius of the base of the cone = 30 cm
Then, Slant Height of the cone = $$\sqrt{16^2+30^2} = \sqrt{256+900} = \sqrt{1156} = 34 cm$$
Curved surface area = $$\pi r L$$ where r = radius of the base of cone, L = Slant height of the cone
= $$\dfrac{22}{7} \times 30 \times 34 = 3205.7 cm^2$$
Rate of painting = Rs.14 per $$cm^2$$
Then, For $$3205.7 cm^2$$, Rate of painting will be $$3205.7 \times 14 = Rs.44880$$