Question 56

If 2x + 3y = 0 and 3x -­ 4y = 34, then x -­ y =

Solution

Equation 1 : 2x + 3y = 0

Multiplying by 3 on both sides, we get : $$6x + 9y = 0$$ -----------(iii)

Equation 2 : 3x -­ 4y = 34

Multiplying by 2 on both sides, => $$6x - 8y = 68$$ -----------(iv)

Subtracting equation(iv) from (iii),

=> $$(6x - 6x) + (9y + 8y) = (0 - 68)$$

=> $$17y = -68$$

=> $$y = \frac{-68}{17} = -4$$

Substituting it in equation (i), we get : $$2x + 3(-4) = 0$$

=> $$2x = 12$$

=> $$x = \frac{12}{2} = 6$$

$$\therefore (x - y) = 6 - (-4) = 6 + 4 = 10$$

=> Ans - (A)


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App