Identify correct statements : (A) Primary amines do not give diazonium salts when treated with $$NaNO_{2}$$ in acidic condition. (B) Aliphatic and aromatic primary amines on heating with $$CHCl_{3}$$and ethanolic KOH form carbylamines. (C) Secondary and tertiary amines also give carbylamine test. (D) Benzenesulfonyl chloride is known as Hinsberg's reagent. (E) Tertiary amines reacts with benzenesulfonyl chloride very easily. Choose the correct answer from the options given below :

We examine each statement in turn.

Statement (A): “Primary amines do not give diazonium salts when treated with $$NaNO_{2}$$ in acidic condition.”
An aromatic primary amine undergoes diazotization as follows: $$ArNH_{2} + NaNO_{2} + 2HCl \xrightarrow{0-5^\circ C} ArN_{2}^{+}Cl^{-} + 2H_{2}O \quad-(1)$$ Aliphatic primary amines give unstable diazonium salts that decompose immediately, but aromatic primary amines do give stable diazonium salts under cold acidic conditions. Therefore the blanket statement “primary amines do not give diazonium salts” is false.

Statement (B): “Aliphatic and aromatic primary amines on heating with $$CHCl_{3}$$ and ethanolic KOH form carbylamines.”
The carbylamine (isocyanide) test is: $$RNH_{2} + CHCl_{3} + 3KOH \xrightarrow{heat} RNC + 3KCl + 3H_{2}O \quad-(2)$$ Both aliphatic and aromatic primary amines give the foul-smelling isocyanide, so statement (B) is correct.

Statement (C): “Secondary and tertiary amines also give carbylamine test.”
Only primary amines have an N-H proton to form the isocyanide. Secondary and tertiary amines do not give this test. Thus statement (C) is false.

Statement (D): “Benzenesulfonyl chloride is known as Hinsberg’s reagent.”
By definition, benzenesulfonyl chloride (PhSO₂Cl) is the Hinsberg reagent used to distinguish amine classes. Hence statement (D) is correct.

Statement (E): “Tertiary amines react with benzenesulfonyl chloride very easily.”
Tertiary amines lack an N-H proton and therefore do not form sulfonamides with PhSO₂Cl. They only form ammonium salts with HCl byproduct: $$R_{3}N + HCl \rightarrow R_{3}NH^{+}Cl^{-} \quad-(3)$$ Thus statement (E) is false.

Therefore the only correct statements are (B) and (D).
The correct answer is Option C: (B) and (D) only.