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A solution of $$H_2SO_4$$ is $$31.4\%$$ $$H_2SO_4$$ by mass and has a density of $$1.25$$ g/mL. The molarity of the $$H_2SO_4$$ solution is M (nearest integer) [Given molar mass of $$H_2SO_4 = 98$$ g mol$$^{-1}$$]
Correct Answer: 4
31.4% H₂SO₄ by mass, density 1.25 g/mL.
In 1 L: mass = 1250 g. Mass of H₂SO₄ = 0.314 × 1250 = 392.5 g.
Moles = 392.5/98 = 4.005 ≈ 4 M. The answer is $$\boxed{4}$$.
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