A person borrowed a sum of ₹30800 at 10% p.a. for 3 years, interest compounded annually. At the end of two years, he paid a sum of ₹13268. At the end of 3rd year, he paid ₹ x to clear of the debt. What is the value of x ?

Amount to be paid after 2 years = 30800(1+$$\frac{10}{100}$$)$$^2$$

= 30800($$\frac{11}{10}$$)$$^2$$

= 30800($$\frac{121}{100}$$)

= ₹37268

Amount paid by the person = ₹13268

Remaining amount = ₹37268 - ₹13268 = ₹24000

Amount to be paid at the end of 3rd year to clear debt(i.e, compound interest on ₹24000 for next 1 year) = 24000(1+$$\frac{10}{100}$$)$$^1$$

$$\Rightarrow$$  x = 24000($$\frac{11}{10}$$)

$$\Rightarrow$$  x = ₹26400

Hence, the correct answer is Option A