The radius of a circle is equal to the length of the rectangle. The circumference of the circle and breadth of the rectangle is 132 cm and 20 cm respectively. The diagonal of the rectangle is:(Take $$\pi = \frac{22}{7}$$)

Let's assume the radius of a circle is 'r'.

Let's assume the length and breadth of the rectangle are 'l' and 'b' respectively.

The radius of a circle is equal to the length of the rectangle.

r = l    Eq.(i)

The circumference of the circle and breadth of the rectangle is 132 cm and 20 cm respectively.

b = 20    Eq.(ii)

circumference of the circle = $$2\times\ \pi\ \times\ r$$

$$132=2\times\frac{22}{7}\ \times\ r$$

$$132=\frac{44}{7}\ \times\ r$$

$$3=\frac{1}{7}\ \times\ r$$

r = 21

From Eq.(i), r = l = 21

diagonal of the rectangle = $$\sqrt{\ l^2\ +\ b^2}$$

= $$\sqrt{\ \left(21\right)^2\ +\ \left(20\right)^2}$$

= $$\sqrt{441+400}$$

= $$\sqrt{841}$$

= 29 cm