In a circle with centre O, points A, B, C and D in this order are concyclic such that BD is a diameter of the circle. If $$\angle$$BAC = 22$$^\circ$$, then find the measure (in degrees) of $$\angle$$COD.

Angle in a semicircle is right angle.

$$\Rightarrow$$  $$\angle$$BAD = 90$$^\circ$$

$$\Rightarrow$$  $$\angle$$BAC + $$\angle$$CAD = 90$$^\circ$$

$$\Rightarrow$$  22$$^\circ$$ + $$\angle$$CAD = 90$$^\circ$$

$$\Rightarrow$$  $$\angle$$CAD = 68$$^\circ$$

Angle subtended by a chord at the center of the circle is twice the angle subtended by the chord on the point of a circle in the same segment.

$$\Rightarrow$$  $$\angle$$COD = 2$$\angle$$CAD

$$\Rightarrow$$   $$\angle$$COD = 136$$^\circ$$

Hence, the correct answer is Option B