Using the given figure, the ratio of $$R_f$$ values of sample A and sample C is $$x \times 10^{-2}$$. Value of $$x$$ is _____

$$R_f = \frac{\text{Distance traveled by the substance from the base line}}{\text{Distance traveled by the solvent from the base line}}$$

• For Sample A:
  $$R_f(A) = \frac{5.0}{12.5}$$
• For Sample C:
  $$R_f(C) = \frac{10.0}{12.5}$$

$$\text{Ratio} = \frac{R_f(A)}{R_f(C)} = \frac{\frac{5.0}{12.5}}{\frac{10.0}{12.5}} = \frac{5.0}{10.0} = 0.5$$

We are given that the ratio is equal to $$x \times 10^{-2}$$:

$$0.5 = x \times 10^{-2}$$ 

$$x = \frac{0.5}{10^{-2}} = 0.5 \times 10^2 = 50$$