Two flasks I and II shown below are connected by a valve of negligible volume.

When the valve is opened, the final pressure of the system in bar is $$x \times 10^{-2}$$. The value of x is _________. (Integer answer)
[Assume : Ideal gas; 1 bar = $$10^5$$ Pa; Molar mass of N$$_2$$ = 28.0 mol$$^{-1}$$; R = 8.31 J mol$$^{-1}$$ K$$^{-1}$$]

$$n_1 = \frac{2.8}{28} = 0.1\ mol$$

$$n_2 = \frac{0.2}{28} = 0.00714\ mol$$

Since the system is insulated,

$$n_1T_1 + n_2T_2 = (n_1+n_2)T_f$$

$$T_f = \frac{n_1T_1+n_2T_2}{n_1+n_2}$$

$$T_f = \frac{(0.1)(300)+(0.00714)(60)}{0.1+0.00714}$$

$$T_f = \frac{30+0.4284}{0.10714}$$

$$T_f = 284K$$

$$V_f = 1L + 2L = 3L = 3\times10^{-3}m^3$$

$$n_f = \frac{2.8}{28}+\frac{0.2}{28} = 0.10714\ mol$$

$$P_f = \frac{n_fRT_f}{V_f}$$

$$P_f = \frac{(0.10714)(8.31)(284)}{3\times10^{-3}}$$

$$P_f = 8.41\times10^4Pa$$

$$1bar = 10^5Pa$$

$$P_f = \frac{8.41\times10^4}{10^5}$$

$$P_f = 0.841bar$$

$$P_f = 84\times10^{-2}bar$$

$$\therefore x = 84$$