Two articles are sold for ₹ 4880, on one, the seller gained 22% and on the other, he lost 20%. What is his overall gain or loss percentage, nearest to one decimal place?

Let the cost price of the first article =x Rs.  and the cost price of the second article =y Rs

sold the price of both article =4880 Rs.

seller getting gain on the first article =22%

seller facing loss on the second article=20%

We know that, $$gain=\dfrac{(Sold price - Cost price)\times 100}{Cost price}$$

$$\Rightarrow 22=\dfrac{(4880 - x)\times 100}{x}$$

$$\Rightarrow 22x=4880\times 100 - 100x$$

$$\Rightarrow 22x+100x=4880\times 100$$

$$\Rightarrow 122x=4880\times 100$$

$$\Rightarrow x=\dfrac{4880\times 100}{122}$$

$$\Rightarrow x=40\times 100$$

$$\Rightarrow x=4000$$Rs.

Hence, the net amount of loss in the first article $$=4880-4000=880$$Rs.

We know that, $$loss=\dfrac{(Cost price -Sold price)\times 100}{Cost price}$$

$$\Rightarrow 20=\dfrac{(y-4880)\times 100}{y}$$

$$\Rightarrow 20y= 100y-4880\times 100$$

$$\Rightarrow 100y-20y=4880\times 100$$

$$\Rightarrow 80y=4880\times 100$$

$$\Rightarrow y=\dfrac{4880\times 100}{80}$$

$$\Rightarrow y=61\times 100$$

$$\Rightarrow y=6100$$Rs.

Hence, the net amount of loss in the second article $$ =6100-4880=1220$$Rs.

Hence, the net loss in the $$=1220-880=340$$Rs.

Total cost price of both the articles is $$6100+4000=10100$$

So overall loss percentage $$=\dfrac{340\times 100}{10100}$$

$$\Rightarrow$$ Required percentage$$=3.4\%$$