The average of eight consecutive odd numbers is 16. If the immediately preceded of the smallest odd number from the given eight odd numbers is also included, then what will be the new average?

The average of eight consecutive odd numbers is 16.

Let's assume the smallest odd number of the given sequence is 'y'.

$$\frac{y+\left(y+2\right)+\left(y+4\right)+\left(y+6\right)+\left(y+8\right)+\left(y+10\right)+\left(y+12\right)+\left(y+14\right)}{8}\ =\ 16$$

$$y+\left(y+2\right)+\left(y+4\right)+\left(y+6\right)+\left(y+8\right)+\left(y+10\right)+\left(y+12\right)+\left(y+14\right)=128$$

$$8y+56=128$$

$$y+7=16$$

y = 16-7

y = 9

If the immediately preceded of the smallest odd number from the given eight odd numbers is also included.

the new average = $$\frac{7+9+11+13+15+17+19+21+23}{9}$$

= $$\frac{135}{9}$$

= 15