Question 53

On a certain principal if the Simple interest for two years is Rs 3000 and Compound interest for the two years is Rs 3225, what is the rate of Interest?

Solution

Let the principal amount = $$Rs. 100x$$ and rate of interest = $$r \%$$

Time period = 2 years

Simple Interest = $$\frac{P \times R \times T}{100} = 3000$$

=> $$\frac{100x \times r \times 2}{100} = 3000$$

=> $$2rx = 3000$$

=> $$x = \frac{3000}{2r} = \frac{1500}{r}$$

Compound Interest = $$P [(1 + \frac{R}{100})^T - 1] = 3225$$

=> $$100x [(1 + \frac{r}{100})^2 - 1] = 3225$$

=> $$100x [(1 + \frac{r^2}{100^2} + 2\frac{r}{100}) - 1] = 3225$$

=> $$(100 \times \frac{1500}{r}) [\frac{r^2}{10000} + \frac{2r}{100}] = 3225$$

=> $$15r + 3000 = 3225$$

=> $$15r = 3225 - 3000 = 225$$

=> $$r = \frac{225}{15} = 15 \%$$

=> Ans - (C)


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