Given, AB = 10 cm, CD = 7 cm, SD = 4 cm and AS = 5 cm
AP and AS are tangents to the circle from point A.
$$\Rightarrow$$ Â AP = AS
$$\Rightarrow$$ Â AP = AS = 5 cm
DR and SD are tangents to the circle from point D.
$$\Rightarrow$$ Â DR = SD
$$\Rightarrow$$Â DR = SD = 4 cm
AB = 10 cm
$$\Rightarrow$$Â AP + BP = 10
$$\Rightarrow$$Â 5 + BP = 10
$$\Rightarrow$$Â BP = 5 cm
CD = 7 cm
$$\Rightarrow$$Â DR + CR = 7
$$\Rightarrow$$Â 4 + CR = 7
$$\Rightarrow$$Â CR = 3 cm
BP and BQ are tangents to the circle from point B.
$$\Rightarrow$$ Â BP = BQ
$$\Rightarrow$$Â BP = BQ = 5 cm
CQ and CR are tangents to the circle from point C.
$$\Rightarrow$$ Â CQ = CR
$$\Rightarrow$$Â CQ = CR = 3 cm
$$\therefore\ $$BC = BQ + CQ = 5 + 3 = 8 cm
Hence, the correct answer is Option D
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