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Question 53
If P = 12 $$\div$$ 6 - 2, Q = 8 $$\div$$ 2 - 3, and R = 18 $$\div$$ 9 + 5, then what is the value of P + R $$\times$$ Q?
Solution
$$P=12\ \frac{6\ }{ }-2$$
$$Q=8\ \frac{\ 2}{ }-3$$
$$R=18\ \frac{\ 9}{ }\ +\ 5$$
P+R*Q
$$P=12\ \frac{\ 6}{ }\ -\ 2$$
$$P=2\ -\ 2$$
$$P=0$$
$$Q=8\ \frac{\ 2}{ }\ -\ 3$$
$$Q=4-\ 3$$
$$Q=1$$
$$R=18\ \frac{\ 9}{ }\ +\ 5$$
$$R=2\ +\ 5$$
$$R=7$$
P=0, Q=1, R=7
$$P\ +\ R\times\ Q$$
$$0\ +\ 7\times\ 1$$
$$7\times\ 1=7$$
Hence, option B is the correct answer
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