Question 53

A student multiplied a number by 11/13 instead of 13/11. What is the percentage error in the calculation?

Solution

Let the number be 143

When the student multiplied it by 11/13, => original result = $$\frac{11}{13} \times 143 = 121$$

When the student multiply it by 13/11, => New result = $$\frac{13}{11} \times 143 = 169$$

=> Percentage error in calculation = $$\frac{(169 - 121)}{169} \times 100$$

= $$\frac{4800}{169} = 28.4\%$$

=> Ans - (B)

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