Of the 5 numbers whose average is 76, the first is 3/7 times the sum of other 4. The first number is
Sum of the five numbers = $$5 \times 76 = 380$$
Let the first number = $$x$$ and Sum of other 4 numbers = $$y$$
According to ques, => $$x = \frac{3}{7} y$$
Also, => $$x + y = 380$$
=> $$\frac{3 y}{7} + y = 380$$
=> $$\frac{3y + 7y}{7} = 380$$
=> $$10y = 380 \times 7 = 2660$$
=> $$y = \frac{2660}{10} = 266$$
$$\therefore$$ The first number = $$x = \frac{3}{7} \times 266$$
= $$3 \times 38 = 114$$
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