In the given figure, if DE $$\parallel$$ BC, AD = 2.5 cm, DB = 3.5 cm and EC = 4.2 cm, then the measure of AC is:

Given, DE $$\parallel$$ BC

$$\triangle$$ADE is similar to $$\triangle$$ABC

$$\Rightarrow$$  $$\frac{AD}{AB}=\frac{AE}{AC}$$

$$\Rightarrow$$  $$\frac{AD}{AD+DB}=\frac{AC-EC}{AC}$$

$$\Rightarrow$$  $$\frac{2.5}{2.5+3.5}=\frac{AC-4.2}{AC}$$

$$\Rightarrow$$  $$\frac{2.5}{6}=\frac{AC-4.2}{AC}$$

$$\Rightarrow$$  2.5AC = 6AC - 25.2

$$\Rightarrow$$  3.5AC = 25.2

$$\Rightarrow$$  AC = 7.2 cm

Hence, the correct answer is Option B