A and B can do a piece of work together in 10 days, B and C can do the same work together in 15 days, while C and A can do the same work together in 20 days. In how many days can A, B and C do the same work, working together?
Let's assume the total work is 60 units.
A and B can do a piece of work together in 10 days.
Efficiency of A and B together = $$\frac{60}{10}$$ = 6 units/day  Eq.(i)
B and C can do the same work together in 15 days.
Efficiency of B and C together = $$\frac{60}{15}$$ = 4 units/day   Eq.(ii)
C and A can do the same work together in 20 days.
Efficiency of C and A together = $$\frac{60}{20}$$ = 3 units/day   Eq.(iii)
From Eq.(i), Eq.(ii) and Eq.(iii), Efficiency of A, B and C together = $$\frac{6+4+3}{2}$$
=Â $$\frac{13}{2}$$
Time taken by A, B and C to do the same work, working together =Â $$\frac{60}{\frac{13}{2}}$$
=Â $$\frac{60\times\ 2}{13}$$
= $$\frac{120}{13}$$ days
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