The platform of a station 400 m longstarts exactly where the last span of a bridge 1.2 km long ends. Howlong will a train 200 m long and travelling at the speed of 72 km/htake to cover the distance between the starting point of the span of the bridge and the far end of the platform ?
distance between the starting point of the span of the bridge and the far end of the platform $$= 400+1200 = 1600 m$$
72 km/h $$=Â 72\times\frac{5}{18}=$$20m/sec
Required time taken $$=Â \frac{1600+200}{20}$$=90 sec = 1.5 min
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