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Number of moles of methane required to produce $$22$$ g $$CO_{2(g)}$$ after combustion is $$x \times 10^{-2}$$ moles. The value of $$x$$ is
Correct Answer: 50
$$CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O$$. 1 mole CH₄ gives 1 mole CO₂ (44 g).
22 g CO₂ = 22/44 = 0.5 mol. So 0.5 mol CH₄ needed = 50 × 10⁻² mol. x = 50.
The answer is $$\boxed{50}$$.
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